P=2(L+W) and P=34 so
2(L+W)=34
L+W=17 so we can say
L=17-W
A=LW using L from above
A=(17-W)W
A=17W-W^2 and A=30 so
30=17W-W^2
W^2-17W+30=0
W^2-2W-15W+30=0
W(W-2)-15(W-2)=0
(W-15)(W-2)=0
So the dimensions of the rectangle are 15 meters by 2 meters.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
x = 4√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Trigonometry</u>
- Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use Pythagorean Theorem.
a = 19
b = x
c = 21
<u>Step 2: Find </u><em><u>x</u></em>
- Substitute: 19² + x² = 21²
- Isolate <em>x</em> term: x² = 21² - 19²
- Evaluate: x² = 441 - 361
- Subtract: x² = 80
- Isolate <em>x</em>: x = √80
- Simplify: x = 4√5
And we have our final answer!
5 because 25 divided by 5 is 5
You have to make the percent a decimal by moving the decimal to the left twice. then you need to multiply the other number.
