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3 years ago

Jeremiah is working on a model bridge. He needs to create triangular components, and he

Mathematics

2 answers:

Darina [25.2K]3 years ago

6 0

Answer:

The answer is No, according to the Triangle Theorem.

Step-by-step explanation:

When you have the sides of the triangle, you must be able to add up 2 sides and have a larger number than the other side.

4+5 = 9 which is greater than 1

5+1 = 6 which is greater than 4

4+1=5 which is equal but not greater than 5

tekilochka [14]3 years ago

3 0

Answer:

No, he would not be able to create a triangle without modifying the lengths of the toothpick

Step-by-step explanation:

In order to determine if the toothpicks can be used to create the triangle, make use of the Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

the square of the longest side of the triangle should be equal to the sum of the square of the two shortest sides

4² + 1²

16 + 1 = 15

5² = 25

15 is not equal to 25

So the lengths cannot be used

the 1 in length would need to be extended by 2 inches to be used

To confirm

3² + 5²

16 + 9 = 25

This is correct

In conclusion, in order to determine if the lengths can be used, check with Pythagoras theorem. If the lengths can be used, the square of the longest side of the triangle should be equal to the sum of the square of the two shortest sides

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Please help i dont get this!

creativ13 [48]

Answer:

The other one is -8 this is because the point on the graph is multiplied by 2

Step-by-step explanation:

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3 years ago

Reflect -4,3 over the x-axis what is it

jasenka [17]

Answer:

-4,-3

Step-by-step explanation:

I think thats right! If not, let me know.

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3 years ago

A bag of chocolates is labeled to contain 0.384 pound of chocolates. The actual weight of the chocolates is 0.3798 pound. Are th

taurus [48]

Answer:

The answer to your question is the chocolates are slightly lighter than the weight stated on the label.

Step-by-step explanation:

Data

The label says 0.384 pounds

Actual mass = 0.3798 pounds

Process

To solve this problem the only thing we must do is substrate the actual weight of chocolates to the weight of chocolates stated on the label.

If the result is positive, then the chocolates are lighter

If the result is negative, then the chocolates are heavier

0.384 pounds - 0.3798 pounds = 0.0042

hmu if you need sumin els!

5 0

4 years ago

Read 2 more answers

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events A and B are independent.

Step-by-step explanation:

The events are defined as follows:

A = a student in the class has a sister

B = a student has a brother

The information provided is:

N = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event X provided that another event Y has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events X and Y are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event A and B as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of B given A as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events A and B are independent.

6 0

4 years ago

Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of er

Vikentia [17]

Answer:

$ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =69$ represent the sample mean for the sample