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Levart [38]
3 years ago
6

Each side of a pentagon is 10 cm greater than the previous side. If the perimeter of this pentagon is 500 cm, find the lengths o

f the sides.
Mathematics
1 answer:
Anton [14]3 years ago
8 0

Answer:

(I'll leave cm out to save space and time in the answer)

the perimeter is 500, there are 5 sides. so on average a side will be 100.

that's already the important key idea.

it's indeed 100 for the third side, the second will be 10 less, the fourth 10 more (making the 2and and the 4th side 200 in sum, and therefore still 100 on average).

repeat this for the 1. and 5. side and we get:

80

90

100

110

120

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The Surface Area of a square pyramid is 3600 ft. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot cu
amm1812

Answer:

10,583 flexible cubes

9915 rigid cubes

Step-by-step explanation:

The equation for the surface area of a square pyramid is area of base plus perimeter of base multiplied by the slant height

Surface area = A + 1/2·p·s

The volume of the pyramid = 1/3×A×h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30·√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, approximately 10,583 cubes

For rigid cubes we have

Given that the height of the pyramid = 30·√7

The slope of the pyramid = 30·√7/10 = 3·√7

So an increase in height of 1 foot gives a reduction in width of 2/(3·√7)

The bottom can hold 400 cubes

The next layer can hold 19×19 = 361

3rd 361

4th 361

5th 324

6th 324

7th 324

8th 324

9th

Continuing, we get a total of about 9915 rigid cubes in the pyramid.

3 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
Read 2 more answers
Find the amount of interest owned for a $1,895 loan for 4 years at a 7.9% interest rate
scoundrel [369]

Answer:

principal (p)=$1895

time (t)=4years

rate(r)=7.9%

Step-by-step explanation:

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X is going to equal two in this equation.
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3 years ago
Arrange the slopes from flattest to steepest.<br><br> -3/2, 0, 4/3, undefined
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To arrange the slopes we need to take their absolute values.
1. U<span>ndefined  slope means a vertical line, so it is going to be steepest.
2.|4/3| = 4/3
3.|-3/2| = 3/2
4. 0  means horizontal line.

</span>From flattest to steepest: 0, -3/2, 4/3, undefined.
8 0
4 years ago
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