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Law Incorporation [45]
3 years ago
5

What are the measures of ∠1 and ∠2?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:232 degress, get rekt idiot

Step-by-step explanation:

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Chris bought a new car for $11,000. If he
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B

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3 years ago
(x^2 + 5x + 2) – (5x^2 – x – 2) =
zlopas [31]

Answer:

{ \tt{( {x}^{2} + 5x + 2) - (5 {x}^{2} - x - 2)  }} \\  = { \tt{(1 - 5) {x}^{2}  + (5 + 1)x + (2 + 2)}} \\  = { \tt{ - 4 {x}^{2} + 6x + 4 }} \\  = { \tt{ - 2(2 {x}^{2} - 3x - 2) }}

3 0
3 years ago
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Use the net below to determine the surface area of the cylinder.
pentagon [3]

The correct answer should be :

Option 3 : 753.6cm^{2}

Hope this helps,

Davinia.

6 0
3 years ago
An object placed between two plane mirrors arranged at right angles to each other at a distance d1 from the surface of one mirro
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5 0
4 years ago
PlZ HELP WILL MARK YOU AS THE BRAINLIEST!
defon

Answer:

1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10

2.  check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9

3. last corner ( -3, 4)

4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42

5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)

6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6

=> area = 3.6x6 =21.6

=> peri = 2x(3.6+6) = 19.2

7. A(-5,4) and B(2,4), AB =  sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base

=> p = peri = 7+ 8.3x2 = 23.6

=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]

             =sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8

5 0
4 years ago
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