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makvit [3.9K]
3 years ago
9

Ooooooooof I need help

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

a) x = -1 and y = -10

Step-by-step explanation:

The first part says find the value of y when the value of x is -3. Then the second part of the question is to find the value of x when the value of y is 2.

so lets solve part a)

y=6x+8\\y=6(-3)+8\\y=-18+8\\y=-10\\\\Now\ when\ y=2\ find\ x\ \\y=6x+8\\2=6x+8\\2-8=6x\\-6=6x\\-6/6=x\\-1=x\\

So answer to part a is x = -1 and y = -10

similarly try the other parts.

You might be interested in
What is the function f(x) = 2(x + 6), find x if f(x) = 22
lord [1]

Answer:

<h3>x = 5</h3>

Step-by-step explanation:

f(x) = 2(x + 6)

f(x) = 22

thereofre we have the equation:

2(x + 6) = 22      <em>use distributive property</em>

2x + 12 = 22     <em>subtract 12 from both sides</em>

2x = 10     <em>divide both sides by 2</em>

x = 5

3 0
3 years ago
Toru takes his dog to be groomed. The fee to groom the dog is $75 plus 7% tax. Is $80 enough to pay for the service? Explain.
weqwewe [10]
80$ won't be enough to pay
He would like need 6 more cents
he needs 80.06$
because


7 0
2 years ago
Quiz 3
erica [24]

Complete question :

The data below represents the number of customers at each Slurpee Sam's Spaghetti Shop. 24, 25, 29, 30, 31, 31, 32, 34, 34. Which box plot correctly summarizes the data?

Answer:

B

Step-by-step explanation:

BOX plots provide information about :

Minimum, Lower quartile, Median, Upper quartile and maximum value of a dataset.

Given the dataset :

24, 25, 29, 30, 31, 31, 32, 34, 34

Minimum value = 24 (Lowest value in the dataset)

First quartile (Q1) = 1/4(n+1)th term

Q1 = 1/4 * 10 = 10/4 = 2.5th term = (25+29)/2 = 27

Second quartile ; median (Q2) = 1/2(n+1)th term

Q2 = 1/2(n+1)th term = 1/2(10) = 5th = 31

Third quartile (Q3) = 3/4(n+1)th term

Q3 = 3/4(n+1)th term = 3/4(10) = 30/4 = 7.5th term = (7th +8th) term = (32 + 34) / 2 = 66/2 = 33

Maximum value = 34 (Highest value in the dataset)

First dot = minimum value

Last dot = maximum value

First line of box = QI

mid line = median

End line of box = Q3

4 0
2 years ago
Describe whether each equation is true for all one or no values of x
aev [14]

Answer:

I'll gladly answer if you could give more information. All we can see is the question "Describe whether each equation is true for all one or no values of x," so we need some context.

Step-by-step explanation:

We need context to this.

7 0
2 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
2 years ago
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