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Crank
3 years ago
5

Multipying these is a pain for me. Please help.

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

a10 b4

Step-by-step explanation:

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Juli2301 [7.4K]

Answer:

option 2 is correct

Step-by-step explanation:

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3 years ago
What is x minus the square root of 2
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x - sqrt(2)

Step-by-step explanation:

x - sqrt(2)

6 0
3 years ago
5(17+13) ÷(8-7) <br> Simply the expression
Scrat [10]
First expand by multiplying
Do 5 x 17=85
Then 5 x 13= 65
As them
85+65=150
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Answer-150
8 0
3 years ago
Read 2 more answers
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
A dog kennel uses 90 lb of dog food per day. How many pounds are used in a year?
Mariulka [41]
32850 pounds are used in a year.
5 0
3 years ago
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