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ludmilkaskok [199]
3 years ago
7

Given f(x) = 3 and g(x) = cos(x). What is Limit of left-bracket f (x) minus g (x) right-bracket as x approaches negative pi?

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

C

cos pie= -1

so (3-(-1)=3+1=4

Step-by-step explanation:

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A salesman earns a Commission of $630 for selling $3050 in merchandise
agasfer [191]

Answer:

ok so lets find what percentage 630 is of 3050

630/3050=0.20655737704

so about 20.7%

Hope This Helps!!!

7 0
2 years ago
How would I solve <br> -6.11 + b = 14.321
Studentka2010 [4]

Answer:

b=20.431

Step-by-step explanation:

you just add  6.11 to both sides. on the left side the -6.11 and +6.11 cancel out and on the right side you will just add 6.11 to 14.321. when you add 14.321 and 6.11 you get 20.431. therefore, b=20.431

8 0
3 years ago
Read 2 more answers
A rectangular pool is 30 1/3 feet long and 12 1/2 feet wide. What is the area of the pool?
HACTEHA [7]
Where t is the time in years

6 0
3 years ago
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A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
Write an equation perpendicular to the line 6x+12y=24 and passing through (4,0)
noname [10]
Y = 2x - 8 is perpendicular to 6x+12y=24 and passes through (4,0)
6 0
3 years ago
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