Question

In the adjoining figure, PQRS is a square and TQRS is a trapezium. If the area of the square PQRS is 25sq.cm and TP=12cm, find the area of trapezium TQRS.​

Answer 1

Answer:

area of square=l²

25sq.cm²=l²

l=5sq.cm

area of trapezium =(1/2)(a+b)h

a=5,b=(12+5)=17,h=5

area of trapezium=(1/2)(22)(5)

area=55cm²

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