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GuDViN [60]
3 years ago
15

The third and fourth grade teachers are planning a trip for their classes to the

Mathematics
1 answer:
exis [7]3 years ago
8 0
The teachers will need three busses, each fitting 99 students.
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To solve the system given below using substitution, it is best to start by solving the second equation for y
Solnce55 [7]

Answer:

47/7, -9/14

Step-by-step explanation:

first you'd solve for x then substitute then find y then substitute the x into the y equation and bam

8 0
4 years ago
Please someone help me
Digiron [165]
26*19=494.
480-494=-14
No. 14$
4 0
3 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
4 years ago
12. What assumption might you be tempted to make about the graphs of y = x, y = x3 and y = x5 based on the values you found in t
ohaa [14]

Answer:

Sorry need the cred

Step-by-step explanation:

8 0
3 years ago
Is 2y-3=4x a direct variationIs 2y-3=4x a direct variation
Margaret [11]

Answer:

2y-3=4x is not a direct variation but is a linaer relationship

Step-by-step explanation:

2Y -3 = 4 X  in slope - intercept form can be written as

2Y = 4 X + 3

Y = 2 X +3/2

Hence this has a y intercept of 3/2

For direct relationship y intercept must be zero . As equation is of one degree hence it is a linear relationship but not a direct one .

7 0
3 years ago
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