2 years ago

Question 1 answer this

2 answers:

8 0

Answer A and Answer D along with the ones you picked beforehand

8 0

Asking how tall everyone in the class is

Asking everyone how long it takes them to get home after school

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Amanda [17]

That is the answer it was to long to write down

8 0

3 years ago

IgorC [24]

It must be the same as it was when constructing the arc above P.

8 0

3 years ago

svet-max [94.6K]

Answer:

Step-by-step explanation:

subtract 5y from both sides of the equation

6 0

3 years ago

katen-ka-za [31]

Both equations are the same
y=−4x+4 ----> y+4x=4,
so consistent dependent

5 0

3 years ago

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

3 years ago