SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ

∵ SR bisects angle TSQ ⇒ given

∴ ∠TSR ≅ ∠QSR

∴ m∠TSR ≅ m∠QSR

∵ ∠T ≅ ∠Q ⇒ given

∴ m∠T ≅ m∠Q

In two triangles RTS and RQS

∵ m∠T ≅ m∠Q

∵ m∠TSR ≅ m∠QSR

∵ RS is a common side in the two triangle

- By using the 4th case above

∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate

Triangle RTS is congruent to RQS by AAS postulate of congruent

Learn more:

You can learn more about the congruent in brainly.com/question/3202836

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3 0

3 years ago

Elenna [48]

Using ratios, 9 : 24
Find ? : 40

Solving Steps-
40 / 24 = 1 2/3

1 2/3 • 9 = 15

ANSWER is 15 L

8 0

4 years ago

DochEvi [55]

${a}^{2} + {b}^{2} = {c}^{2} \\ {8}^{2} + {5}^{2} = {c}^{2} \\ 64 + 25 = {c}^{2} \\ 89 = {c}^{2} \\ \sqrt{89} = {c}^{2} \\ 9.4 = c$

4 0

3 years ago