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Nostrana [21]
3 years ago
13

0.26 - 106-100 - 106

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

-311.74

Step-by-step explanation:

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Order the numbers from least to greatest<br><br>-3,9,0,-11,7,-6
igor_vitrenko [27]

-11 ,-3, -6, 0, 7, 9 I hope im right


7 0
3 years ago
Speed = distance divided by time taken. car 1 travels 10 miles every 5 minutes. car 2 travels 30 miles every 20 minutes. what is
Setler [38]
Car 1
2 miles............................1 minute
10 miles.........................5 minutes
20 miles.........................10 minutes
40 miles..........................20 minutes
car2
1.5 miles...........................1 minute
15miles.............................10 minutes
30 miles...........................20 minutes
the difference is 0.5 miles per minute

0.5*60=30 miles/hour
5 0
3 years ago
66.21 was rounded to 2dp. what is the lower bound?
sladkih [1.3K]

Answer:

the answer is 66.205

Step-by-step explanation:

basically you look at the place value so

66.21 is basically the same as 66.210 then you look at the lowest number that can round UP to 66.210 which would be out of 1 to 9 would be 5 so the smallest number that can round up to 66.210 is 66.205 hope this helped :D

4 0
3 years ago
PLEASE HELP DUE TODAY!! GIVING BRAINLIEST, REPORTING BITLY ANSWERS
bulgar [2K]

Answer:

Minimum: 50

Lower Quartile:  59

Median:  66

Upper Quartile: 74

Maximum: 92

Step-by-step explanation:

50, 55, 58, 60, 62, 64, 68, 70, 72, 76, 84, 92

Minimum: 50

Lower Quartile: (58 + 60)/2 = 59

Median: (64 + 68)/2 = 66

Upper Quartile: (72 + 76)/2 = 74

Maximum: 92

5 0
3 years ago
Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has
Inessa05 [86]

Answer:

for(j = n; j > 0; j--)

System.out.print(\"*\");

Step-by-step explanation:

-A for loop is a repetition control structure.

-It allows the efficiency to write a loop that would otherwise be written a couple of times.

-The output is a single line comprising n asterisks,

-The number of asterisks printed will be equivalent to the n-value declared.

7 0
3 years ago
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