Hey ! there
Answer:
- <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>
Step-by-step explanation:
In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>
For finding volume of sphere , we need to know its formula . So ,
<u>Where</u><u> </u><u>,</u>
- π refers to <u>3.</u><u>1</u><u>4</u>
- r refers to <u>radius</u><u> of</u><u> sphere</u>
<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>
Now , we are substituting value of π and radius in the formula ,
Simplifying it ,
Cancelling 3 with 3 :
We get ,
Multiplying 4 and 3.14 :
Multiplying 12.56 and 9 :
- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
Please take a photo of this problem... it looks very hard when it is written in the way you did.
<h3>
If I am reading this correctly the answer should be 1,977,326,743x^3</h3>
Answer:
w = 5
Step-by-step explanation:
(26+4)=30, and 30/6=5, therefore, w = 5.
Answer:
Just put it in Geogebra classic. It's an app that helps very much with functions!