Which graph represents the solution to the system of inequalities? y ≥ x – 5 y < –x + 4
1 answer:
We want to solve the system of inequalities
y ≥ x - 5
y < -x + 4
The line y = x - 5 has
slope = 1
y-intercept = -5
x-intercept: x - 5 = 0 => x = 5
The line y = -x + 4 has
slope = -1
y-intercept = 4
x-intercept: -x + 4 = 0 => x = 4
Answer:
Graph the two lines and apply the inequalities as shown in the figure.
The shaded area is the solution region.
y ≥ x - 5
y < -x + 4
The line y = x - 5 has
slope = 1
y-intercept = -5
x-intercept: x - 5 = 0 => x = 5
The line y = -x + 4 has
slope = -1
y-intercept = 4
x-intercept: -x + 4 = 0 => x = 4
Answer:
Graph the two lines and apply the inequalities as shown in the figure.
The shaded area is the solution region.
You might be interested in
If you're using the app, try seeing this answer through your browser: brainly.com/question/3242555
——————————
Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
![\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5Ccdot%20%281-sin%5E2%5C%2Cx%29-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2-2%5C%2Csin%5E2%5C%2Cx-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B-%5C%2C%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7Bsin%5C%2Cx%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D)
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)
——————————
Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)
Answer:
<em>Sali's speed was 18.75 km/h.</em>
Step-by-step explanation:
Jane took 3.5 hours to cycle the 63 km.
As, , so the speed of Jane will be:
Suppose, the speed of Sali is km/h
Sali caught up with Jane when they had both cycled 30 km.
So, <u>the time required for Jane to cycle 30 km</u> and <u>the time required for Sali to cycle 30 km</u>
Given that, Sali started to cycle 4 minutes or after Jane started to cycle. So, the equation will be.......
Thus, the speed of Sali was 18.75 km/h.