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Liula [17]
3 years ago
11

What is the image point of (-4, 8) after a translation right 4 units and up 2 units?

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

Given:

Point = ( -4,8).

To find:

The image point of (-4, 8) after a translation right 4 units and up 2 units.

Solution:

We know that, if a figure translated 4 units right and 2 units up, then the rule of translation is

(x,y)\to (x+4,y+2)

The point is (-4,8).

Putting x=-4 and y=8, we get

(-4,2)\to (-4+4,8+2)

(-4,2)\to (0,10)

Therefore, the image of point (-4,8) is (0,10).

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the straight line L has the equation 4y=5x+3. Point A has the coordinates (3,-2) Find the equation of the line straight line tha
Aleonysh [2.5K]

Answer:

y = - \frac{4}{5} x + \frac{2}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 4y = 5x + 3 into this form by dividing the 3 terms by 4

y = \frac{5}{4} x + \frac{3}{4} ← in slope- intercept form

with slope m = \frac{5}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{4} } = - \frac{4}{5} , thus

y = - \frac{4}{5} x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - \frac{12}{5} + c ⇒ c = - 2 + \frac{12}{5} = \frac{2}{5}

y = - \frac{4}{5} x + \frac{2}{5} ← equation of perpendicular line

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3 years ago
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Step-by-step explanation:

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3 years ago
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den301095 [7]
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Subtract 2x from the left side and the right side. Then you get -y = -2x+6. The divide each side by negative 1. Thus getting you to an answer of y = 2x-6
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