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Korvikt [17]
3 years ago
12

How much money would you need to deposit today at 7% annual interest

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

$33,090.

Step-by-step explanation:

The formula is A = P( 1 + r/2)^2n so we have:

50,000 = P(1 + 0.07/2)^(6*2)

50000 = P * 1.035^12

P = 50000/ 1.035^12

= $33,090 to the nearest dollar.

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Solve for y<br> -5x-y&lt;3
valentinak56 [21]
-5x - y < 3.....add y to both sides
-5x < y + 3...subtract 3 from both sides
-5x - 3 < y.....or y > -5x - 3 
8 0
3 years ago
Check my answer please
Aleksandr [31]
So it is an isosceles triangle that means that the bottom two angles are equal...
so 
40 = 5x 
divide both sides by 5 and you get 8

now the triangle angles add up to 180
we make an equation out of it...
(2y + 20 ) + ( 5(8)) + 40 = 180
2y + 20 + 40 + 40 = 180
combine like terms
2y + 100 = 180
so subtract 100 from both sides
2y = 80
divide by 2 to isolate the variable
y = 40

You are correct!!! :)
5 0
3 years ago
How do I find the values of x and y?
zepelin [54]
All 3 angles =180...
3 0
4 years ago
Which is the y-intercept of the relationship represented in the table?
lozanna [386]

Answer:

y = x - 4

Step-by-step explanation:

m, gradient = (5  - 3)/(9-7) = 1

Formula : x - x1 = m( y - y1 )

y - 3 = 1 ( x -7)

Equation : y = x -4

6 0
3 years ago
For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x &lt; -3h(x) = { 5, for - 35x&lt;5for
sleet_krkn [62]

Given the piecewise function h(x):

h(x)=\begin{cases}-5x-13,x

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

h(x)=-5x-13

Replace the expression with x=-6 and calculate the corresponding value of x:

\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

h(x)=5

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that:

h(0)=5

3) For h(5), you have to determine the value of h(x) for x=5, for values of x greater than or equal to 5, h(x) has the following shape:

h(x)=x+1

Replace the expression with x=5 and calculate the corresponding value of h(x):

\begin{gathered} h(5)=5+1 \\ h(5)=6 \end{gathered}

4) For h(9), you have to determine the value of h(x) when x=9, 9 is greater than 5, for this value of x, the function has the following shape:

h(x)=x+1

Replace the expression with x=9, and calculate the corresponding value of h(x):

\begin{gathered} h(9)=9+1 \\ h(9)=10 \end{gathered}

So, to sum up:

undefined

5 0
1 year ago
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