Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
x=2
y=3
Solution:
First we find common denominators. It is "xy". Then we multiply numerators by common denominator. We get followings:
(4y-3x)/xy=1; (6y+15x)/xy=8
Then
4y-3x=xy;
6y+15=8xy
Multiply first equasion by 5
20y-15x=5xy
Now we add two equasions to get one
20y-15x=5xy
6y+15x=8xy
We get
26y=13xy
Cut "y" and we will find "x"
26=13x
x=2
Put x value into the first equasion(4y-3x=xy) to find out "y"
4y-6=2y
2y=6
y=3
The answer is x bc when you decreasing the interval f(x) it will equal (-2)
(7 points) A) 7 B) 1.5 C) Does not exist D) 2