Answer:
Probability that a randomly selected student plays sport and is in band = 1/50
Step-by-step explanation:
Total number of students= 1900
Percentage of those that play sport and are in band = 2%
Hence those that play sport and are in band = 2/100 x 1900 = 38 students
Probability that a randomly selected student plays sport and is in band = 38/1900 = 1/50
X= 7
y=77
im not 100% though
<h3>
Answer: D) 72</h3>
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Work Shown:
Angle PQR = (far arc - near arc)/2
2x+72 = ( (2x+252) - (2x+108) )/2
2x+72 = 144/2
2x+72 = 72
2x = 72-72
2x = 0
x = 0/2
x = 0
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Angle PQR = 2x+72
Angle PQR = 2(0)+72
Angle PQR = 72 degrees
Answer:
The second answer, and possibly the first answer as also true.
She did run a test that would indicate its an unbalanced dice, but this wasn't tried out with a different person throwing the dice.
Step-by-step explanation:
This is because from the computer generator results we see 11 of the 25 values are estimating at 1/5 when we know dice are 1/6 and more than 1/2 show just under 1/5 which balances this to be 1/6
But there are 9/25 tests that showed values under 10 throws found a 6 in 9/25 events = 1/3 approx out of 1/10 of the throws, and 1/3 is still a higher value than 1/6 of the multiple throws so indicates 100 throws would not be enough to tell as we cannot possibly assume her results are comparable with a computer generator.As the computer generator completed 25 x 100 throws and have just compared only x10 in relation to 1/10 of the events of the generated computer. This showing 9 of the 25 (100) throw events in relation scores 1/3 of the results a 6. The answer is she would need to throw somewhere between 1000 and 3000 to compare to the computers results.
