The answer is no, the side lengths are not persevered. <span />
Answer:
6
Step-by-step explanation:
Given information:
Interior angle of a polygon cannot be more that 180°.
One interior angle = ![80^{\circ}](https://tex.z-dn.net/?f=80%5E%7B%5Ccirc%7D)
Other interior angles are = ![128^{\circ}](https://tex.z-dn.net/?f=128%5E%7B%5Ccirc%7D)
Let n be the number of sides of the polygon.
Sum of interior angles is
![Sum=80+128(n-1)](https://tex.z-dn.net/?f=Sum%3D80%2B128%28n-1%29)
![Sum=80+128n-128](https://tex.z-dn.net/?f=Sum%3D80%2B128n-128)
Combine like terms.
.... (1)
If a polygon have n sides then the sum of interior angles is
![Sum=(n-2)180](https://tex.z-dn.net/?f=Sum%3D%28n-2%29180)
.... (2)
Equating (1) and (2) we get
Isolate variable terms.
Divide both sides by 52.
Therefore the number of sides of the polygon is 6.
Answer:
65/24 or 2 17/24
Step-by-step explanation:
4 1/8 - 1 5/12
= 33/8 - 17/12
= 33/8(3/3) - 17/12(2/2)
= 99/24 - 34/24
= 65/24