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2 years ago

The graph of a quadratic function intercepts the x-axis in two places and the y-axis in one place.

Mathematics

1 answer:

solmaris [256]2 years ago

4 0

The true statement about the quadratic function is that it has two distinct real zeros

<h3>How to interpret the quadratic function?</h3>

The given parameters are:

x-intercepts = 2 i.e. intercepts the x-axis in two places
y-intercept = 1 i.e. intercepts the y-axis in one place

The first highlight above means that, the function can be represented as:

y = a(x - x1)(x -x2)

Where x1 and x2 are the x-intercepts

This also means that the quadratic function has two distinct real zeros

Read more about quadratic functions at:

brainly.com/question/7323175

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3 years ago

Given f(x) =

sergejj [24]

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = \left\{ \begin{array}{ll} 2\cos(\pi x) \text{ for } x \leq -1 \\ \\ \displaystyle \frac{2}{\cos(\pi x)}\text{ for } x > -1 \end{array} \right.$

And we want to find:

$\displaystyle \lim_{x\to -1}f(x)$

So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

Left-Hand Limit:

$\displaystyle \lim_{x\to-1^-}f(x)$

Since we are approaching from the left, we will use the first equation:

$\displaystyle =\lim_{x\to -1^-}2\cos(\pi x)$

By direct substitution:

$=2\cos(\pi (-1))=2\cos(-\pi)=2(-1)=-2$

Right-Hand Limit:

$\displaystyle \lim_{x\to -1^+}f(x)$

Since we are approaching from the right, we will use the second equation:

$=\displaystyle \lim_{x\to -1^+}\frac{2}{\cos(\pi x)}$

Direct substitution:

$\displaystyle =\frac{2}{\cos(\pi (-1))}=\frac{2}{\cos(-\pi)}=\frac{2}{(-1)}=-2$

So, we can see that:

$\displaystyle \displaystyle \lim_{x\to-1^-}f(x)=\displaystyle \lim_{x\to -1^+}f(x) =-2$

Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

$\displaystyle \lim_{x \to -1}f(x)=-2$

Our answer is A.

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3 years ago