Question

Help please and thank you ​

Answer 1

Answer:

  D

Step-by-step explanation:

We assume the rotation R is counterclockwise 60°.

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The exponent on R is the number of times it is applied. That is, R² = R(R(figure)). So, the composition is equivalent to R^(2-4) = R^-2.

When the exponent of R is negative, it is essentially the inverse function. That is, applying the function R to the result will give the figure you started with. Equivalently, it is rotation in the other direction.

  $(\mathcal{R}^2\circ\mathcal{R}^{-4})(\text{figure})=\mathcal{R}^{-2}(\text{figure})=\text{figure rotated 120^{\circ} CW}$

The point 120° clockwise from B is D.

The desired image point is D.