The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
<h3>What is an aqueous reaction in
equilibrium?</h3>
When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.
δG = − R T ln
R = universal gas constant 8.313
δG= 20. 46 kj/mol
T = 298 k or 24.4 in celcius.
substituting the value in the equation.
20. 46 kj/mol = 8.313 × 24.4 in celcius × K
K = 8.313 × 24.4 in celcius / 20. 46 kj/mo
k = 9.91 mol .
Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
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Explanation:
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Answer:
Final temperature of the gas = -146.63 °C
Explanation:
At constant pressure, volume and temperature of the gases are related as:
Where,
V1 = Initial volume = 1.00 L
V2 = Final volume = 2.40 L
T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K
Now, substitute the values in the above equation,
T2 = 126.52 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
T( °C) = T(K) - 273.15
= 126.52 - 273.15 = -146.63 °C
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