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Karolina [17]
2 years ago
14

List three facts or accomplishments of Modern India (India today)​

Chemistry
1 answer:
viva [34]2 years ago
8 0

Answer:

India is one of the oldest countries in the world and is found in the Asian continent of the world.

They are known as the most populous country in the world.

They also have a greater linguistic diversity than any other large country. Lots of languages are available and accepted in the country.

They are very vast in Agriculture and accounts for 40percent of Mango production in the world

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What are the cations and anions whose compounds are usually soluble?
HACTEHA [7]

Answer: -

Solubility of a substance depend on the balance of intermolecular forces between the solvent and solute, and the entropy change that accompanies this process.

Temperature and pressure also plays a role in solubility.

A solution having Group 1 cations like lithium, sodium, potassium etc are always soluble.

A solution having NH₄⁺ is soluble.

All salts with anion as nitrates, acetates, chlorates, and perchlorates are soluble in water.

8 0
2 years ago
Ms. Sharkey wanted to see which tennis shoes made her run the fastest. She bought
Svetach [21]

Answer:

to compare the data she has got?

7 0
3 years ago
Naturally occurring element X exists in three isotopic forms: X-28 (27.979 amu, 92.21% abundance), X-29 (28.976 amu 4.70% abunda
bezimeni [28]

<u>Answer:</u> The average atomic mass of X is 28.09 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 27.979 amu

Percentage abundance of isotope 1 = 92.21 %

Fractional abundance of isotope 1 = 0.9212

  • <u>For isotope 2:</u>

Mass of isotope 2 = 28.976 amu

Percentage abundance of isotope 2 = 4.70 %

Fractional abundance of isotope 2 = 0.0470

  • <u>For isotope 3:</u>

Mass of isotope 3 = 29.974 amu

Percentage abundance of isotope 3 = 3.09 %

Fractional abundance of isotope 3 = 0.0309

Putting values in equation 1, we get:

\text{Average atomic mass of X}=[(27.979\times 0.9212)+(28.976\times 0.0470)+(29.974\times 0.0309)]

\text{Average atomic mass of X}=28.09amu

Hence, the average atomic mass of X is 28.09 amu

4 0
3 years ago
Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

4 0
2 years ago
Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d.
patriot [66]

Answer:

I got the answers but it won't let me post it correctly on here....

Explanation:

9.) 10-2.76 =0.0174 [H30+]= 1.74*10-3 M

10.)10-3.65=0.00224  [H3O+] =2.24*10-2 M

11.)10-3.65=0.00224 [OH-]= 2.224*10-4M

12.)10-6.87=0.00000135  [OH-]= 1.35*10-7M

3 0
2 years ago
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