Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3 What is the mass in grams of 17.16 mL of acetone?

Chemistry

1 answer:

Mashutka [201]3 years ago

8 0

1 mL = 1 cm³

D = m / V

0.7857 = m / 17.16

m = 0.7857 x 17.16

m = 13.482 g

You might be interested in

MAY SOMEONE HELP ME PLZZ

makkiz [27]

Answer: Rubber source, temperature, thinkness, thread design, driving pattenrs, weather, etc.

Explanation: There are many variables. Here are a few I would include in a tire lifetime study:

1. Type of rubber, including source

2. Thickness of tire

3. Design of tire thread

4. Life as a function of average speed and road surface

5. Expected outside temperature and wet conditions

6. Driving conditions of speed and both acceleration and deceleration parameters (e.g., tire life when slamming on the brakes or accelerating quickly)

5 0

2 years ago

12. If the total pressure exerted by 3 gases is 45 atm and each individual gas has the

Bumek [7]

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

3 0

3 years ago

How many moles are in 7.2x10^15 atoms of Pb?

fiasKO [112]

<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb$