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3 years ago

Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3 What is the mass in grams of 17.16 mL of acetone?

Chemistry

1 answer:

Mashutka [201]3 years ago

8 0

1 mL = 1 cm³

D = m / V

0.7857 = m / 17.16

m = 0.7857 x 17.16

m = 13.482 g

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The specific heat of lead is 0.129 J/gC. Find the amount of heat released when 2.4 moles of lead are cooled from 37.2C to 22.5

labwork [276]

Answer:

-943J or 943J released

Explanation:

m=2.4 mol x 207.g/ mol=497.3g

c=.129 J/gC

T= T f-Ti=(22.5-37.2)=-14.7C

Q=?

Q=(49.3g)(.129 J/g C) (-14.7 C)

= -943 J or 943 J released

6 0

3 years ago

is 0.0410 M−1 s −1 . We start with 0.105 mol C2F4 in a 4.00-liter container, with no C4F8 initially present. What will be the co

Jet001 [13]

Answer:

After three hours, concentration of C₂F₄ is 0.00208M

Explanation:

The rate constant of the reaction:

2 C2F4 → C4F8 is 0.0410M⁻¹s⁻¹

As the units are M⁻¹s⁻¹, this reaction is of second order. The integrated law of a second-order reaction is:

$\frac{1}{[A]} =\frac{1}{[A]_0} +Kt$

<em>Where [A] and [A]₀ represents initial and final concentrations of the reactant (C₂F₄), K is rate constant (0.0410M⁻¹s⁻¹) and t is time of the reaction (In seconds). </em>

3.00 hours are in seconds:

3 hours ₓ (3600 seconds / 1 hour) = 10800 seconds

Initial concentration of C2F4 is:

0.105mol / 4.00L = 0.02625M

Replacing in the integrated law:

$\frac{1}{[A]_0}= \frac{1}{0.02625} +0.0410M^{-1}s^{-1}*10800s\\\frac{1}{[A]_0}=480.9M^{-1}$

[A] = 0.00208M

<h3>After three hours, concentration of C₂F₄ is 0.00208M</h3>

5 0

3 years ago

Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -> Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which

kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

7 0

3 years ago

What is the best way to make a supersaturated solution?

pishuonlain [190]

Answer:

A. Heat the solution

Explanation:

To make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 mL of water at 80 degrees Celsius. When the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.

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3 years ago

How can you separate a mixture containing two different liquids? filtration evaporation distillation magnetic attraction

maxonik [38]

Distillation I believe.....

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4 years ago