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finlep [7]
3 years ago
15

Can anyone help me with this problem

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer: I need you to zoom in more on the paper.

The paper looks blurry and fuzzy to me.

Step-by-step explanation:

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Gym A charges $60 a month plus $5 per visit. The monthly cost at Gym B is represented by y = 7x + 40, where x is the number of v
Anarel [89]

Answer:

See the explanation

Step-by-step explanation:

Given data

Gym A charges $60 a month plus $5 per visit

let the number of visits be x, and the total charge be y

Hence the total charge is expressed as

y=5x+60--------------1

Gym B is represented by

y = 7x + 40-----------2

Although I can not find any option, we can conclude that gym A monthly charge is $20  more expensive than gym B

6 0
3 years ago
Of the 320 students in 8th grade, 3/8 have a pet. How many students in 8th grade have a pet?
Zepler [3.9K]
12 please help answer my question which is why is the uks biome like it is?
7 0
3 years ago
Read 2 more answers
(05.06) A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours t
Anestetic [448]

Answer: The company can build 10 child bikes and 12 adult bikes in the week .

Step-by-step explanation:

Let 'c' be the number of child bike and 'a' be the number of adult bike.

According to the problem

The restriction of building time for a week is 4c+6a≤120 hours.........(1)

and the restriction of testing time for a week is 4c+4a≤100 hours...............(2)

Lets check whether company can build c=10 and a=12 bikes in a week by putting this value in (1) and (2)

(1)......4(10)+6(12)=40+72=112≤120 ⇒Restriction of building time is satisfied.

(2)......4(10)+4(12)=40+48=88≤100⇒Restriction of testing time is satisfied.

Hence,  the company can build 10 child bikes and 12 adult bikes in the week,as order is meeting with the restrictions.

4 0
3 years ago
Read 2 more answers
to get to work truman waited 11 minutes for the bus, then travled 21.78 miles on the bus at a speed of 33 miles per hour how muc
alexgriva [62]
We have 11 as our base value, meaning that we add 11 to something, so we have 11+<something>. To find that something, we want to know how long it takes to go 21.78 miles at 33 miles per hour. To get this, we want to turn miles per hour into minutes per mile and multiply that by 21.78 miles to get our answer. Therefore, we cross them out as shown in the equation to get \frac{21.78 miles}{1} * \frac{1 hour}{33 miles}  * \frac{60 minutes}{1 hour}

6 0
4 years ago
George needs to rent a car for one day. He can rent a Cadillac from Gamma Car Rental for $30.39 per day plus 55 cents per mile.
oksian1 [2.3K]
Call the number of days 'd' and the number of miles 'm'.
(Original, eh ?)

Then the equation for Gamma's price is

                           Price-G = 30.39d + 0.55m

and the equation for Delta's price is

                            Price-D = 50.31d + 0.43m .

We're going to set the prices equal, and find out
what the number of miles is:

                       Price-G = Price-D.

        30.39d + 0.55m  = 50.31d + 0.43m .

Before we go any farther, I'm going to assume that both cases would be
one-day rentals.  My reasons:  ==> the solution for the number of miles
depends on how many days each car was rented for;  ==> even if both
cars are rented for the same number of days, the solution for the number
of miles depends on what that number of days is.

For 1-day rentals, d=1, and

                                        30.39 + 0.55m  =  50.31 + 0.43m .
Beautiful.  Here we go.
Subtract 0.43m
from each side:              30.39 + 0.12m  =  50.31

Subtract 30.39
from each side:                            0.12m  =  19.92

Divide each side by 0.12 :                  m  =  166 .

There it is !  If a car is rented from Gamma for a day, and another car
is rented from Delta for a day, and both cars are driven 166 miles, then
the rental prices for both cars will be the same ... (namely $121.69)
4 0
3 years ago
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