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Harrizon [31]
3 years ago
6

Please someone should help me solve it 2x ÷ x^ - 4

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

The answer is

<h2>{2x}^{5}</h2>

Step-by-step explanation:

<h3>\frac{2x}{ {x}^{ - 4} }</h3>

First of all separate the two from the x

That's

<h3>\frac{2(x)}{ {x}^{ - 4} }</h3>

Next we use the rules of indices

Since they have the same base and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{2(x)}{ {x}^{ - 4} }  = 2( {x}^{1 -  - 4)}  = 2( {x}^{1 + 4} )</h3>

We have the final answer as

<h3>{2x}^{5}</h3>

Hope this helps you

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Since, y varies inversely as x.

\therefore \: y  =  \frac{k}{x}  \\ (k = constant \: of \: proportionality) \\  \therefore \: xy = k...(1) \\ plug \: y =  \frac{2}{5}  \: and \: x = 2 \: in \: (1) \\  2\times \frac{2}{5}   = k \\  \implies \: k =  \frac{4}{5}  \\ substituting \: k=  \frac{4}{5}  \: in \: (1) \\ xy =  \frac{4}{5} ..(2) \\ this \: i s \: the \: equation \: of \: variation \\ plug \: x = 1 \: in \: (2) \\ 1 \times y =  \frac{4}{5}  \\  \huge \red{ \boxed{y =   \frac{4}{5}  }}

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