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Harrizon [31]
3 years ago
6

Please someone should help me solve it 2x ÷ x^ - 4

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

The answer is

<h2>{2x}^{5}</h2>

Step-by-step explanation:

<h3>\frac{2x}{ {x}^{ - 4} }</h3>

First of all separate the two from the x

That's

<h3>\frac{2(x)}{ {x}^{ - 4} }</h3>

Next we use the rules of indices

Since they have the same base and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{2(x)}{ {x}^{ - 4} }  = 2( {x}^{1 -  - 4)}  = 2( {x}^{1 + 4} )</h3>

We have the final answer as

<h3>{2x}^{5}</h3>

Hope this helps you

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Step-by-step explanation:

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2 years ago
The expression is 3 (x+4)-(2x+7) what is that equivalent too
posledela

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x+19

Step-by-step explanation:

3x+12 - 2x+7 = x+19

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Read 2 more answers
Can y'all please help.
sattari [20]

Answer:

See explanation

Step-by-step explanation:

<u>Step 1.</u> Substitute for d to solve for n:

From the first equation:

d=70-n

Then substitute it into the second equation:

0.1(70-n)+0.05n=5.5\\ \\7-0.1n+0.05n=5.5\\ \\7+(-0.05n)=5.5\\ \\-0.05n=5.5-7=-1.5\\ \\n=\dfrac{-1.5}{-0.05}=30

<u>Step 2:</u> Substitute for n to solve for d:

d+n=70\\ \\d+30=70\\ \\d=70-30=40

There are 40 dimes and 30 nikels in the piggy bank

6 0
3 years ago
A bank lent $200,500 for the development of two products. If the loan for priduct X was for $50,500 more than that for product Y
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Answer:

$75,000

Step-by-step explanation:

Let

x ----> amount lent for product X

y ---->amount lent for product Y

we know that

A bank lent $200,500 for the development of two products

so

x+y=200,500 ----> equation A

The loan for product X was for $50,500 more than that for product Y

so

x=y+50,500 ----> equation B

substitute equation B in equation A

y+50,500+y=200,500

solve for y

2y=200,500-50,500\\2y=150,000\\y=\$75,000

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