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Blizzard [7]
3 years ago
9

9. Jenn went to the farmer's market with $40.00. She bought a 10 lb bag of potatoes for $6.00, a pie for $8.00, 4 qt fresh blueb

erries for $4.00 per qt, and 5 lb of apples at $1.49 per lb. What
percent of the $40.00 did she still have when she left?
93.625%
6.375%
25%
.0595%
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:  the answer is 6.375% because I just took the test

Step-by-step explanation:

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Suppose f(x) is a function such that if p
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I think in a function of f(x) P is also another variable like P is the price then Q is the quantity.

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one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt
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Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

 \text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A

⇒ \text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A

= \frac{3-1}{3} A

= \frac{2}{3} A

\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B

⇒ \text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B

But, Again according to the question,

The total population that claims that they are from A =  one half of the total population of A and B.

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B

⇒ \frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B

⇒ \frac{1}{6} A = \frac{1}{4} B

⇒ A =\frac{6}{4}B

⇒ \frac{A}{B} =\frac{3}{2}

8 0
3 years ago
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