Answer:
Step-by-step explanation:
<u>Initial coordinates and transformations:</u>
- (x, y) → (4x, 4y) → (3x, 3y)
- A(-1, -1) → A'(-4, -4) → A''(-3, -3)
- B(1, 1) → B'(4, 4) → B''(3, 3)
- C(2, 0) → C'(8, 0) → C''(6, 0)
Some are said more than once but they is 10 different choices together so it’s be ‘1/10 probability’
7 + (-3x^2) for x = 0 7 + [-3(0)^2]; = 7 + -3(0); = 7 - 0; = 7
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
