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Rus_ich [418]
3 years ago
12

a sample of carbon is burnt at a rate of 0.70 gram per second for 40 minutes to generate heat write a balanced equation for the

reaction and determine the volume​
Chemistry
1 answer:
Schach [20]3 years ago
6 0

Answer:

0.00015dm³

Explanation:

the equation gives

C + O2 — CO2

40min × 60s/1min = 2400s

0.70g/s ÷ 2400s =0.00029g

no of mole = mass/molar mass

molar mass of Co2 = 44g/mol

no of mole = 0.00029/44 = 6.59×10^-6mol

volume at STP since its a gas

1 mol — 22.4dm³

6.59×10^-6 — 22.4×6.59×10^-6/1 = 0.00015dm³

*this is the only way i could think of so am not 100% sure

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SEP Use Math In another experiment, a chemist combines 7.2 grams of carbon with 19.2 grams of oxygen to form a compound. Identif
babunello [35]

Step 1 - Remembering the law of mass conservation

As stated by the law of mass conservation, in a chemical process no atoms can be created or destroyed. Consequently, the mass of the system will not change: the sum of the masses of reactants will be exactly equal the sum of the masses of products.

Step 2 - Using the law of mass conservation to understand the problem

The law of mass conservation therefore guarantees that, if we are mixing 7.2 g of C with 19.2 g of O, we will form 7.2+19.2 g of whatever is the product. Therefore we will form 26.4 g of product, which will be either CO or CO2.

Step 3 - Using mass percentage to find the correct product

Since we already know what will the mass of the product be, we can calculate the percentage of C in the product:

\text{ \%(C)=}\frac{7.2}{26.4}\times100=27.3\text{ \%}

Now, let's calculate the percentage of C in both CO (28 g/mol) and CO2 (44 g/mol), remembering that the molar mass of C is 12 g/mol:

\begin{gathered} CO\to\text{ \%(C)=}\frac{12}{28}\times100=42.8\text{ \%} \\  \\ CO_2\to\text{\%(C)=}\frac{12}{44}\times100=27.3\text{ \%} \end{gathered}

We can see that in CO2 the amount percent of C is exactly the same as we have calculated for the unknown product of this reaction. Therefore, the product is CO2.

3 0
1 year ago
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A small hole in the wing of a space shuttle requires a 20.7-cm² patch.
cricket20 [7]

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Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

Patch area of the space shuttle is 20.7 cm²

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or, 1 cm² = (0.00001 km)²

or,  1 cm² = 10⁻¹⁰km²

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20.7 cm² = 2.07 × 10⁻⁹ km²

The patch area in square kilometers is 2.07 × 10⁻⁹ km²

To learn more about unit conversion, visit: brainly.com/question/11543684

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