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Gnesinka [82]
3 years ago
5

A technique to bring changes in the

Business
1 answer:
son4ous [18]3 years ago
8 0

Explanation:

A technique to bring changes in the

entire organization, rather man

focusing attention on individuals to

bring changes easily is Organizational development

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The expected average rate of return for a proposed investment of $500,000 in a fixed asset, with a useful life of four years, st
Natalka [10]

Answer: 48%

Explanation:

Based on the information given, the average rate of return will be:

= (Average return) / (Average Investment) x 100

where, average return will be:

= ($240000 × 4)/4

= $240000

Then, annual averay rate of return will be:

= $240000/$500000 × 100

= 48%

6 0
3 years ago
If we were able to invest a Gradient = $100 at the end of each year for 7 years at 6% interest (i.e., So at the end of year 1, $
zavuch27 [327]

Answer:

We can withdraw an equivalent annuity of  $ 293.658 each year.

Explanation:

We build a scheduled table to know the future value of the gradient investment

Time    Beg        Gradient          Total             Rate Ending

1  $100.00   $100.00  $100.00           0.060   $106.00

2  $106.00   $100.00   $206.00   0.060   $218.36

3  $218.36   $200.00   $418.36   0.060   $443.46

4  $443.46   $300.00   $743.46   0.060   $788.07

5  $788.07   $400.00   $1,188.07   0.060   $1,259.36

6  $1,259.36   $500.00   $1,759.36   0.060   $1,864.92

7  $1,864.92   $600.00   $2,464.92   0.060   $2,612.81

Then, we solve for the equivalent annuity-due:

PV \div \frac{1-(1+r)^{-time} }{rate}(1+rate) = C\\

PV 2,613

time 7

rate 0.06

2612.81 \div \frac{1-(1+0.06)^{-7} }{0.06}(1+0.06) = C\\

C  $ 293.658

Itis annuity due as we will going to retire cash in a 6 year period for  seven times. (at each year-end during 6 years thus, annuity-due

1st      2nd     3rd   4th    5th    6th   7th

/-------/-------/-------/-------/-------/-------/-------/

         1       2       3        4      5        6       7

3 0
3 years ago
In about 100 words, outline the advantages of using RFID technology instead of bar code scanning technology in managing the inve
STatiana [176]

Answer:

(1) RFID TAGS FROM A GREATER DISTANCE THAN BARCODE WHEN TAGGING INVENTORIES.

(2) RFID TAGS CAN BE READ AT A FARTHER DISTANCE THAN BARCODE.

(3) RFID TAG MUST NIT BE IN LINE WITH THE SCANNER FOR IT TO IDENTIFY AND READ INVENTORIES.

Explanation:RFID(RADIO FREQUENCY IDENTIFICATION) uses electromagnetic fields to track and identify by reading and capturing the information stored on a tag attached to an object. It is a generally accepted and has been widely used in variety of industries including Supply chain,Human resources, inventory management etc

(1) RFID TAGS FROM A GREATER DISTANCE THAN BARCODE WHEN TAGGING INVENTORIES.

(2) RFID TAGS CAN BE READ AT A FARTHER DISTANCE THAN BARCODE.

(3) RFID TAG MUST NOT BE IN LINE WITH THE SCANNER FOR IT TO IDENTIFY AND READ INVENTORIES.

7 0
3 years ago
Managers today need to look past traditional viewpoints in determining the success of their company's strategy. One such approac
bogdanovich [222]

Answer:

The Balanced Scorecard

Customer satisfaction:

Perspective: Customer: This perspective concentrates on things like customer service.

Goal:  Service: This would be the level of customer service.

Measure:  How do our customers see us? Survey: This would be the results of an online customer satisfaction survey.

Internal processes:

Perspective: Internal business: This perspective focuses on the things that a company has to do internally to meet and exceed customer expectations.

Goal: Productivity: This would concentrate on changes to the process involved in production.

Measure: How do we look to our shareholders?  Analysis: This would use data from the ERP system to look into success levels of company processes.

Innovation and improvement activities:

Perspective: Innovation and Learning: This perspective is concerned with making sure employees learn and grow so they can continually innovate.

Goal: Training: This would focus on providing enhanced training opportunities for employees.

Measure: What do we need to excel at? Results: This would look at changes in the skill level of employees.

Financial measures:

Perspective: Financial: This perspective has to do with the conversion of performance into financial performance and the creation of value.

Goal: Growth: This would concentrate on an increase in sales.

Measure: Can we continue to improve and create value?  Sales: This would be the annual sales figures.

Explanation:

The balanced scorecard which Bryan is developing for KanO Mines helps KanO Mines to understand how to create value in the organization.  With the balanced scorecard as a strategic planning and management tool, organizational goals are communicated to KanO Mines, so that his daily activities are aligned with the organizational strategy.  It also helps him to prioritize his projects, products, and services.  The balanced scorecard does not only deal with perspectives and goals, it also helps KanO Mines and his manager, Bryan, to measure and monitor his progress towards achieving the set organizational strategic goals.

4 0
3 years ago
Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,
wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is  = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time =  mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be I_i :

I_i = \dfrac{R^2}{\mu (\mu-R)}

I_i = \dfrac{2.1^2}{5 (5-2.1)}

I_i = \dfrac{4.41}{5 (2.9)}

I_i = \dfrac{4.41}{14.5}

\mathbf{I_i = 0.30}

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

\delta = \dfrac{R}{\mu}

\delta = \dfrac{2.1}{5}

{\delta = 0.42}

\mathbf{\delta = 42}

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - \delta

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58  × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0
3 years ago
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