After n years, the deposit made at birth will have a value equal to;
FV1 = C(1+r)^n = 1000(1+0.018)^n = 1000(1.018)^n
After n years, the yearly deposits made at every birthday will have a value equal to;
FV2 = P{(1+r)^n-1}/r = 750{(1+0.018)^n-1}/0.018 = 41666.67 {(1.018)^n-1} = 41666.67 (1.018)^n -41666.67
Total FV = FV1+FV2 = 1000(1.018)^n+41666.67(1.018)^n-41666.67 = 42666.67 (1.018)^n - 41666.67
Answer:
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Answer:
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