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KatRina [158]
3 years ago
14

I don't even know how to figure this out. I don't have a formula for this

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

\sin\theta=\dfrac{15}{17}

?=15

Step-by-step explanation:

Use the trigonometry formula

\cos^2\theta+\sin^2\theta=1

You are given that

\cos \theta=\dfrac{8}{17}

Substitute into the first formula

\left(\dfrac{8}{17}\right)^2+\sin^2\theta=1\\ \\\dfrac{64}{289}+\sin^2\theta=1\\ \\\sin^2\theta=1-\dfrac{64}{289}=\dfrac{289-64}{289}=\dfrac{225}{289}\\ \\\sin \theta=\pm \dfrac{15}{17}

Angle \theta is acute angle, then the sine of this angle is positive and

\sin\theta=\dfrac{15}{17}

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A company has 10 trucks. A truck has 15 pallets. A pallet has 7 boxes. A box has 50 containers. A container has 3 plastic bags.
Oliga [24]

Step-by-step explanation:

5160 In two trucks they have a 50 specimen , 10 , 20

6 0
2 years ago
Suppose $886.20 is listed for $5 less. A third catalog has $886.20 marked down 20% ,which is the better deal?
Ipatiy [6.2K]

Answer:

20% of $886.20 is 177.24 so the better deal would be 20% off

Step-by-step explanation:

4 0
2 years ago
A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4
katrin2010 [14]

Answer:- A reflection of the line segment across the line y = –x .


Explanation:-

A reflection over the line y = -x, the x-coordinate and y-coordinate interchange their places and they are negated (the signs are changed).

Given :- A line segment has endpoints at (–1, 4) and (4, 1) such that it reflects produce an image with endpoints at (–4, 1) and (–1, –4).

(-1, 4)→(-4, 1) and

(4, 1)→(-1, -4)

Thus this shows a reflection of the line segment across the line y = –x.

4 0
2 years ago
Read 2 more answers
Help me please I NEED to pass this
Alina [70]

OPTION C is the correct answer.

Hope it helps you.

4 0
2 years ago
An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 3ft long with a diameter of 2.2 ft . S
Contact [7]

4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5 ft^{3} per minute.

Step-by-step explanation:

              The given is,

                         Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.

                          Oil drained at a rate of 2.5 ft^{3} per minute.

Step:1

       Time taken to dry the oil tank is,

                           T   = \frac{Volume of oil}{Oil drain rate}  ....................................(1)

Step:2

      Volume of the oil is,

                           V = \pi  r^{2} h.................................................(2)

      Where, r - Radius of Cylinder

                             r = \frac{d}{2}

                             r = \frac{2.2}{2}

                             r = 1.1 ft

      From eqn (1),

                        V =  \pi × 1.1^{2} × 3

                           = 11.40398 ft^{3}

Step:3

     From equation (1)

                           = \frac{11.40398}{2.5}

                           = 4.56

                           = 4.56 minutes

                      T  = 4 minutes 34 seconds

Result:

      Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.

4 0
2 years ago
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