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KatRina [158]
3 years ago
14

I don't even know how to figure this out. I don't have a formula for this

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

\sin\theta=\dfrac{15}{17}

?=15

Step-by-step explanation:

Use the trigonometry formula

\cos^2\theta+\sin^2\theta=1

You are given that

\cos \theta=\dfrac{8}{17}

Substitute into the first formula

\left(\dfrac{8}{17}\right)^2+\sin^2\theta=1\\ \\\dfrac{64}{289}+\sin^2\theta=1\\ \\\sin^2\theta=1-\dfrac{64}{289}=\dfrac{289-64}{289}=\dfrac{225}{289}\\ \\\sin \theta=\pm \dfrac{15}{17}

Angle \theta is acute angle, then the sine of this angle is positive and

\sin\theta=\dfrac{15}{17}

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storchak [24]

Answer:

A = 70 mm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (b₁ + b₂)

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 10, b₁ = 10, b₂ = 4 , then

A = \frac{1}{2} × 10 × (10 + 4) = 5 × 14 = 70 mm²

7 0
3 years ago
The vertex angle of an isosceles triangle measures 40°. What is the measure of a base angle?
skad [1K]
In all triangles, inner angles add to 180 degrees.
In an isosceles triangle, the base angles are the same and the vertex angle is different from the rest.

b= (180-40)/2
b= 140/2
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Step-by-step explanation:

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3 years ago
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Answer:

(a) -6

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Answer:

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4 0
3 years ago
Read 2 more answers
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