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KatRina [158]
3 years ago
14

I don't even know how to figure this out. I don't have a formula for this

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

\sin\theta=\dfrac{15}{17}

?=15

Step-by-step explanation:

Use the trigonometry formula

\cos^2\theta+\sin^2\theta=1

You are given that

\cos \theta=\dfrac{8}{17}

Substitute into the first formula

\left(\dfrac{8}{17}\right)^2+\sin^2\theta=1\\ \\\dfrac{64}{289}+\sin^2\theta=1\\ \\\sin^2\theta=1-\dfrac{64}{289}=\dfrac{289-64}{289}=\dfrac{225}{289}\\ \\\sin \theta=\pm \dfrac{15}{17}

Angle \theta is acute angle, then the sine of this angle is positive and

\sin\theta=\dfrac{15}{17}

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Is 12/42=10/35 a true proportion
olya-2409 [2.1K]
Yes, they both are 2/7

Proof: Left-hand side

Simplify the following:
12/42

The gcd of 12 and 42 is 6, so 12/42 = (6×2)/(6×7) = 6/6×2/7 = 2/7:
Answer:  2/7
Right-hand side:

Simplify the following:
10/35
The gcd of 10 and 35 is 5, so 10/35 = (5×2)/(5×7) = 5/5×2/7 = 2/7:
Answer:  2/7
3 0
3 years ago
The track-and-field coach wants to know whether the students in the entire school prefer track races or field events. The coach
strojnjashka [21]

All students in each grade

audience: <u>students</u> - counts for both boys and girls.

option (B) for teachers is irrevelant.

option (C) doesn't include girls.

option (D) doesn't include the entire school

Hence, option A is correct.

8 0
2 years ago
A $280 suit is marked down by 30%. Find the sale price.<br> The sale price is $
storchak [24]

Answer:

84

Step-by-step explanation:

30% * $280

\frac{}{100}

= 84

So, the sale price is $84

3 0
2 years ago
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A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0
3 years ago
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Answer:

What question do we answer?

Step-by-step explanation:

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3 years ago
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