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Rashid [163]
2 years ago
7

Which statement about friction in a system is true?(1 point)

Physics
1 answer:
ohaa [14]2 years ago
7 0

Answer:

I thinks its d ----------

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A satellite orbits the earth at a speed of 8.0x 10^3m/s . Calculate the period of orbit of the satellite if the distance between
gladu [14]

Hi there!

The period of an orbit can be found by:

T = \frac{2\pi r}{v}

T = Period (? s)
r = radius of orbit (6400000 m)

v = speed of the satellite (8000 m/s)

This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.

Let's plug in what we know and solve.

T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}

8 0
1 year ago
A car drives for 30 km with a speed of 30m/s. How much time does it take the car to travel this distance?
Artist 52 [7]

                   Time  =  (distance)  /  (speed)

                           =  (30 km)  /  (30 m/s)

                           =  (30,000 m)  /  (30 m/s)

                           =  (30,000 / 30)  sec

                           =      1,000 seconds

                           =      16 minutes  40 seconds  
6 0
3 years ago
If the total momentum of a system is changing:
DENIUS [597]

Answer:

(d) a net external force must be acting on the system

Explanation:

Momentum is given as the product of mass and velocity.

P = MV

According to Newton's second law of motion, " Force applied to a body (system) is directly proportional to the rate of change of momentum of the body (system) which takes place in the direction of the applied force (external force).

F ∝ΔMV

Therefore, If the total momentum of a system is changing, a net external force must be acting on the system.

(d) a net external force must be acting on the system

3 0
3 years ago
A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m
Marrrta [24]

Answer:

-1.47 m/s^2

Explanation:

We can use the following SUVAT equation to solve the problem:

v^2 - u^2 = 2ad

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

a=\frac{v^2-u^2}{2d}=\frac{0-(24)^2}{2(196)}=-1.47 m/s^2

4 0
2 years ago
URGANT!!!!!!! NEED ANSWERS TODAY!!!!
natima [27]
2H2 + O2 = 2H2O + Energy
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