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ehidna [41]
3 years ago
9

Suppose f(x) - x = 2/ x. Fincd f(- 3)

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

To find the mode you need to check the number which is more often repeated in the set than the other.But as you can see here there is no number which is repeated more often than the other everyone is repeated once,so in this case  we say that the set of data values has no mode.

To find the the range of the set of data you need to first place the numbers in ascending order (as it is already in) and then find the greatest and the smallest number and subtract them.

Range :

10,20,30,40,50,60,70,80,90,100,110,120,130,140,150.

Greatest number = 150.

Smallest number = 10.

Subtract = 150-10 = 140.

Step-by-step explanation:

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Please help will mark brainliest
asambeis [7]

The total cost of the tent is 409.86

------------------------------------------------------

explanation:

230×0.65=149.50

230+149.50=379.50×.08=30.36

379.50+30.36=409.86

(Hope this helps :) )

5 0
2 years ago
Read 2 more answers
Find the equation of a line with m = 3 that passes though the point (-12,<br> 4).
Viefleur [7K]

Answer:

y = 3x + 40

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3 , then

y = 3x + c ← is the partial equation

To find c substitute (- 12, 4 ) into the partial equation

4 = - 36 + c ⇒ c = 4 + 36 = 40

y = 3x + 40 ← equation of line

8 0
2 years ago
Small gift box to hold a ring shaped like a cube the box measures 1.4 inches on each side what is the volume of the gift box rou
d1i1m1o1n [39]
So first you do  length x width x height in this case 1.4 x 1.4 x 1.4
5 0
2 years ago
A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost
Tanya [424]
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
\frac{6p}{3p^{2}}=\frac{6}{3p} times \frac{p}{p}=\frac{2}{1p} times \frac{p}{p} times \frac{3}{3}=\frac{2}{1p}  times 1 times 1=2/p

easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1


each member pays 2/p

4 0
3 years ago
ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
2 years ago
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