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dmitriy555 [2]
3 years ago
11

What is the value of the expression shown when n = 6?

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

8 less then the quotient of 42 and a number

a " quotient " is the result of division

(42 / n ) - 8.....when n = 6

(42/6) - 8 =

7 - 8 =

-1

so when n = 6, the expression = -1

Step-by-step explanation:

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The temperature is -3°C. As the day progresses, the temperature increases by 8°C, then drops by 6°C. Find the final temperature.
Volgvan

We know that the initial temperature is -3 then it rises to 8 and drops by 6 degrees then you just need to subtract six from 8                                                         \displaystyle\  8-6=2^\circ \\\\Answer: the\ secondary\ temperature \ will \ be equal \ to  \ 2^\circ

8 0
3 years ago
Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (9,8) Midpoint (0,9)​
shepuryov [24]

Answer:

(-9, 10)

Step-by-step explanation:

The location of the midpoint of a line with endpoint at (x_1,y_1) and (x_2,y_2) is given as (x, y). The location of x and y are:

x = \frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

Given the endpoint (9,8) and Midpoint (0,9), the location of the other endpoint can be gotten from:

0=\frac{9+x_2}{2}\\ \\9+x_2=0\\\\x_2=-9\\\\Also,9=\frac{8+y_2}{2}\\ \\8+y_2=18\\\\y_2=18-8\\\\y_2=10

Hence the endpoint is at (x2, y2) which is at (-9, 10)

5 0
3 years ago
The reduced fraction of 1902/21
mars1129 [50]
So i got 90 4/7 reduced in fractions
5 0
3 years ago
Read 2 more answers
The cosine of 23° is equivalent to the sine of what angle
Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

\cos(90^\circ-x)=\sin(x)

or

\sin(90^\circ-x)=\cos(x)

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"
aivan3 [116]

Answer:

6

Step-by-step explanation:

\sqrt[3]{216} = \sqrt[3]{8} · \sqrt[3]{27}  =  \sqrt[3]{2}³ · \sqrt[3]{3}³ = 2 x 3  = 6

7 0
2 years ago
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