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yawa3891 [41]
3 years ago
11

VOCABULARY Is 5 in the solution set of x + 3 >8 ?

Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

d. no; If x is 5, the expression on the left simplifies to 8, making the inequality false.

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A baseball team had 28 hime runs last year. This year they have 20 homeruns. What was the percent of change
dexar [7]

Answer:

28.57% drop

Step-by-step explanation:

Number of runs

  • Last year = 28
  • This year = 20

Change this year:

  • 28 - 20= 8

Change %:

  • 8/28*100  = 28.57% drop
8 0
3 years ago
5 - x/3 for x = -3<br><br> Evaluate the expression
Vladimir [108]
The answer is 6. When x is -3 then you divide -3 by 3 and the quotient is -1. So 5-(-1) is also equal to 5+1 which equals 6
6 0
3 years ago
The skoblickis are building a new home. The scale drawing below shows their master bedroom. Find the length and width of the act
jolli1 [7]

Answer:

Length: 20

Width:15

Step-by-step explanation:

Hope this Helps!

3 0
3 years ago
Danny's Bike Shop sells a certain model of racing bike for $550. The same bike can be bought at a competing shop for 7 percent l
AleksAgata [21]

Answer:

$511.5

Step-by-step explanation:

Given: Selling price of bike at Danny´s shop is $550

           Bike is sold 7% less at competitor´s shop.

Lets find the discounted amount at Danny´s competitor shop.

∴ \frac{7}{100} \times 550 = \$ 38.5

Now, finding the cost of bike at Danny´s competitor.

Cost of bike at Danny´competitor= (\textrm{Price at dannys shop - discount provided by competitor})

Cost of bike at Danny´s competitor= 550-38.5= \$511.5

∴ Cost of bike at Danny´s competitor is $511.5.

6 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
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