4 1/2-3 5/8=0.875 or 875/1000 or 35/40 or 7/8
Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
So the equation is A = P(1+rt)
A = 10,000(1+0.07*6)
A = 10,000(1+0.42)
A = 14,200.00
Answer: BM = 21.4
Step-by-step explanation:
Considering the given triangle BMS, to determine angle BM, we would apply the sine rule. It is expressed as
m/SinM = s/SinS = b/SinB
Where m, s and b are the length of each side of the triangle and angle M, Angle S and angle B are the corresponding angles of the triangle.
From the information given,
Angle M = 102°
Angle B = 35°
Angle S = 180 - (102 + 35) = 43°
b = MS = 18
s = BM
Therefore
18/Sin 35 = BM/Sin 43
Cross multiplying, it becomes
BMSin35 = 18 × Sin 43
BM × 0.5736 = 18 × 0.6820
0.5736BM = 12.276
Dividing the left hand side and the right hand side of the equation by 0.5736, it becomes
0.5736BM/0.5736 = 12.276/0.5736
BM = 21.4
Answer:
6
Step-by-step explanation:
2+4 = 6
..............
