This triangle would be acute none of the angles are greater than or equal to 90.
a) We know that the probability Jane will win is 0.2, and draws is 0.3, which leaves the probability of her losing to be 0.5 (1 - 0.2 - 0.3 = 0.5).
I'll begin by filling in for the first game:
win = 0.2, draw = 0.3, lose = 0.5
Next, we'll fill in for if she wins, draws, or loses the second game. The probabilities would be the same as the first game for the second game.
Win (0.2): win = 0.2, draw = 0.3, lose = 0.5
Draw (0.3): win = 0.2, draw = 0.3, lose = 0.5
Lose (0.5): win = 0.2, draw = 0.3, lose = 0.5
b) To find the probability that Jane will win both games, we need to multiply the probability of Jane winning the first game by the probability of her winning the second game.
0.2 x 0.2 = 0.04
Hope this helps! :)
If the width is 2p then the width of both sides is 4p. Subtract that from the total perimeter and you get 16p-4p= 12p. Divide that by two because there are 2 side lengths. So, one side length is 6p.
Answer:
5, 7
Step-by-step explanation:
Answer:
(Factor out 2x from the expression)
2x (x +3)
