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hoa [83]
3 years ago
6

Tristan invested $470

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0
Well Tristan better get it together
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John caught a gigantic tuna fish. Every 1/100 of it could fill up a can of tuna fish. How many cans of tuna fish can it make?
Hoochie [10]

Answer:

100

Step-by-step explanation:

if every 1/100 is 1 tuna can you need to multiply the amount of tuna to make a tuna can so it will be 1 so times 100

6 0
2 years ago
What is the area of this face?​
Paladinen [302]

Answer:

242 ft^2

Step-by-step explanation:

15 x 14 + 4 x 8 = 242 ft^2

(break down the polygon into two rectangles)

6 0
3 years ago
A car travels 17 miles on one gallon of gas
zmey [24]

When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,

Step-by-step explanation:

Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.

Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;

x = 17y, this represents the relation between x and y.

To find the gallons in the tank, y = \frac{x}{17},

For x = 170, y = \frac{170}{17} = 10,

Similarly equating the values we get that when x = 187, y = 11,

when x = 204, y = 12,

when x = 221, y = 13,

when x = 238, y = 14,

when x = 255, y = 15,

when x = 272, y = 16,

when x = 289, y = 17,

when x = 306, y = 18,

when x = 323, y = 19,

when x = 340, y = 20,

8 0
2 years ago
A cone and a triangular pyramid have a height of 9.3 m
Otrada [13]

Answer:

x=17.1\ in

Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m  and their cross-sectional areas are equal at every level  parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the  pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level  parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]

simplify

\pi r^{2}=\frac{1}{2}(b)(h)

we have

r=3\ in\\b=3.3\ in\\h=x\ in\\pi=3.14

substitute the given values

(3.14)(3)^{2}=\frac{1}{2}(3.3)(x)

solve for x

28.26=\frac{1}{2}(3.3)(x)

x=28.26(2)/3.3\\x=17.1\ in

7 0
3 years ago
Read 2 more answers
Please help ASAP I am so confused
mixer [17]

Here are the steps, hope it helps!

3 0
2 years ago
Read 2 more answers
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