The answer would be 7,6,5,4,3,2,1 inches tall in the chronological order
The missing value of the solution to the equation y = −2x + 4, is: 3.
<h3>What is the Solution to an Equation?</h3>
The solution to a given equation, is the x and y values of an ordered pair that would make the equation true, if we substitute their values into the equation.
Given the equation, y = -2x + 4, and we have (x, -2) as the solution where the value of x is the missing value in the solution, to find the value of x, substitute y = -2 into the equation and solve for x:
-2 = -2x + 4
Subtract 4 from both sides
-2 - 4 = -2x + 4 - 4 (subtraction property of equality)
-6 = -2x
Divide both sides by -2
-6/-2 = -2x/-2
3 = x
x = 3
Therefore, the missing value is: 3.
Learn more about the solution to an equation on:
brainly.com/question/25678139
#SPJ1
<span>A rectangular soccer field is twice as long as it is wide. If the perimeter of the soccer field is 300 yards , what are its dimensions?
I know the basic formula is 2W+2L=300 but i am not sure where to go from there...
-----
Equations:
2W + 2L = 300
L = 2W
----
Substitute for "L" and solve for "W":
</span><span>2W + 2(2W) = 300
6W = 300
W = 50 yds (width)
----
Solve for "L":
L = 2W
L = 100 yds (length)
========================
Cheers.
</span>
I got 3 quarts... this is the last one I'm doing cause you are mad at me and want nothing to do with me. hope u get the rest of your answers and bye.
Answer:
.
Step-by-step explanation:
If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is 
.
Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)
Hence, β = - 3 and α + a = 1 and α - a = -3
Now, solving those two equations of α and a we get,
2α = - 2, ⇒ α = -1 and
a = 1 - α = 2.
Now, eccentricity of the hyperbola is given by ![b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20a%5E%7B2%7D%28e%5E%7B2%7D%20%20-%201%29%20%3D%204%5B%28%5Cfrac%7B5%7D%7B2%7D%20%29%5E%7B2%7D%20-1%5D%20%3D%2021)
{Since 
given}
Therefore, the equation of the given hyperbola will be
. (Answer)
