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lutik1710 [3]
3 years ago
13

How much is 60% of 12 liters of milk

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:

7.2 liters of milk

Step-by-step explanation:

<u>60%</u> x 12 liters of milk = 7.2 liters of milk

100

gulaghasi [49]3 years ago
6 0
It will be 7.2 liters of milk
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The number a point corresponds to on a number line is called it's
cestrela7 [59]
It's called a coordinate
8 0
3 years ago
If 0.00005893 is expressed in the form 5.893 × 10n, what is the value of n ?
yan [13]
In the scientific value of 5.893 x 10n. The standard value is 0.00005893 what is n? To better illustrate this phenomenon, we can explain it further under the rules of scientific notation.
For example. <span><span>
1. </span><span> 3 x 10^3 = 3 x 100 = 300</span></span>
<span><span>2. </span><span> 3 x 10^-3 = 3 x 0.001 = 0.003</span></span>

Solution:
0.00005893 = 5.893 x 0.00001 = 5.893 x 10^-5  
n= ^-5



7 0
3 years ago
15b^2+20y^3<br> Find the greatest common factor
Andrew [12]

Answer:

Hope this helps!

Step-by-step explanation:

The GCF is 5

8 0
3 years ago
Una heladeria dispone de 20 frutas distintas para elaborar sus malteadas. Si los clientes pueden elegir tres sabores para mezcla
Dahasolnce [82]

Answer:

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

Step-by-step explanation:

En este caso, el cliente que adquiere una malteada de tres sabores distintos sigue el siguiente procedimiento:

1) El primer sabor sale de cualquiera de las 20 frutas disponibles.

2) El segundo sabor es distinto al primer sabor, es decir, que sale de las 19 frutas restantes.

3) El tercer sabor es distinto al primer sabor y al segundo sabor, es decir, que sale de las 18 frutas restantes.

Puesto que existe una doble conjunción y que puede importar el orden según la preferencia del cliente, se habla matemáticamente de una permutación, definida como:

n\mathbb{P}k = \frac{n!}{(n-k)!} (1)

Donde:

n - Número de sabores disponibles, adimensional.

k - Número de sabores escogidos, adimensional.

Si tenemos que n = 20 y k = 3, entonces la cantidad de malteadas de tres sabores distintos es:

n\mathbb{P}k = \frac{20!}{(20-3)!}

n\mathbb{P}k = \frac{20!}{17!}

n\mathbb{P}k = 20\cdot 19\cdot 18

n\mathbb{P}k = 6840

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

5 0
3 years ago
Pleaseeeee help I’m begging someone I PROMISE. I will mark brainlest
Lerok [7]

Answer:


Step-by-step explanation:

a) x>0 → items can not be negative

b) c(2,000) = 5,000+1.3(2,000) = $7,600

c)5,000+1.3x<10,000

5,000-5,000+1.3x<10,000-5,000

1.3x<5,000

x<3846 items


5 0
4 years ago
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