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Dovator [93]
2 years ago
15

HELP! WILL GIVE BRAINLEST!

Mathematics
1 answer:
bulgar [2K]2 years ago
4 0

Answer:

A

Step-by-step explanation:

tan theta will equal zero if theta = n × pi where n is an integer

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an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor
Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • The Z-score measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

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In this problem:

  • Mean of 8.8 inches, thus \mu = 8.8.
  • Standard deviation of 2.8 inches, thus \sigma = 2.8.

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

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25th percentile:

  • X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = -0.675(2.8)

X = 6.91

75th percentile:

  • X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = 0.675(2.8)

X = 10.69

The IQR is:

IQR = 10.69 - 6.91 = 3.78

What is the diameter, in inches, of the smallest tree that is an outlier?

  • The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

10.69 + 1.5(3.78) = 16.36

The diameter of the smallest tree that is an outlier is of 16.36 inches.

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A similar problem is given at brainly.com/question/15683591

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2 years ago
Which statements are true regarding the area of circles &amp; sectors? Check all that apply.
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Answer:

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Step-by-step explanation:

7 0
3 years ago
Find a ratio equivalent to 15/60
Flauer [41]

Answer:

\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}

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\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

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Multiply the numerator and the denominator by the same number:

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10 equal parts. that is the answer
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