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velikii [3]
3 years ago
13

2. to 1) A 13-foot ladder is leaning against a wall 5 feet from the base of the wall. How far above the ground does the ladder t

ouch the wall? *Simplest radical form* A) 144 ft B) 14 ft C) 144 ft D) /194 ft​
Mathematics
1 answer:
Degger [83]3 years ago
5 0

Answer:

12 ft

Step-by-step explanation:

You have a right triangle with the hypotenuse = 13 and one leg = 5

Let x = distance above the ground that the ladder touches the wall

Now use the Pythagorean theorem

x^{2}  + 5^{2} = 13^{2} \\x^{2}  + 25 = 169\\x^{2}  = 144\\x = \sqrt{144} = 12

It looks like none of the choices are correct, because the answer is 12 ft.

By the way, it is impossible for the ladder to reach up the wall a distance longer the the length of the ladder.  Think about it.  OK?

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Please help will give brainliest please
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20

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rounding it to the nearest degree will also be 20

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An astronaut is returning to Earth in a spacecraft. If the spacecraft is descending at a rate of 13.81 kilometers per minute, wh
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p: If two out of five people use the subway every day, then the probability of a person using the subway is 0.4.
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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

(\left {{20} \atop {2}} \right. )=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

(\left {{3} \atop {2}} \right. )=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

\frac{3}{190}\\ =0.01579\\=0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0
2 years ago
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