Answer:
1 1/3 pound (1 pound and 1/3)
Step-by-step explanation:
u just but it in a fraction
4/3
and simplify to mixed number
1 1/3
And isosceles triangle always equals 180 degrees so to find the value of x what number would you need for the value to be 180
Answer with explanation:
Using following law of indices
![1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}](https://tex.z-dn.net/?f=1.x%5Ea%20%5Ctimes%20x%5Eb%3Dx%5E%7Ba%2Bb%7D%5C%5C%5C%5C2.%20%28x%5Em%29%5En%3Dx%5E%7Bmn%7D%5C%5C%5C%5C%203.%20x%5E%7B-n%7D%3D%5Cfrac%7B1%7D%7Bx%5En%7D%5C%5C%5C%5C4.%20%5Cfrac%7Bx%5Em%7D%7Bx%5En%7D%3Dx%5E%7Bm-n%7D)
![1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}](https://tex.z-dn.net/?f=1.5%5E%7B-1%7D%5Ctimes%203%5E%7B-2%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ctimes%5Cfrac%7B1%7D%7B3%5E2%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B5%5Ctimes9%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B45%7D%5C%5C%5C%5C2.%20%5Cfrac%7Bmn%5E%7B-4%7D%7D%7Bp%5E0%2Aq%5E%7B-2%7D%7D%3D%5Cfrac%7Bmq%5E2%7D%7Bn%5E4%7D%5C%5C%5C%5C%203.0.0042%3D4.2%5Ctimes%2010%5E3%5C%5C%5C%5C4.6.12%20%5Ctimes%2010%5E3%3D6.12%20%5Ctimes%201000%3D6120%5C%5C%5C%5C%205.0.5%20%5Ctimes%288%5Ctimes10%5E5%7D%29%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes8%20%5Ctimes%2010%5E5%3D4%5Ctimes%2010%5E5%5C%5C%5C%5C6.%20%289%20%5Ctimes%2010%5E3%29%5E2%3D9%5E2%20%5Ctimes%20%2810%5E3%29%5E2%3D81%20%5Ctimes%2010%5E6%5C%5C%5C%5C7.%28%20%5Cfrac%7B1%7D%7B2%7Da%5E%7B-4%7D%5Ctimes%20b%5E2%20%29_%7Ba%3D-2%2Cb%3D4%7D%7B%5Ctext%7Bor%7D%7D%28%20%5Cfrac%7B1%7D%7B2%7Da%5E%7B4%7D%5Ctimes%20b%5E%7B-2%7D%20%29_%7Ba%3D-2%2Cb%3D4%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28-2%29%5E%7B-4%7D%5Ctimes%284%29%5E2%7B%5Ctext%7Bor%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28-2%29%5E%7B4%7D%5Ctimes%284%29%5E%7B-2%7D%3D%5Cfrac%7B16%7D%7B2%5Ctimes16%7D%3D%5Cfrac%7B1%7D%7B2%7D)
![9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9](https://tex.z-dn.net/?f=9.%20%284%5Ctimes%20x%5Ctimes%20y%5E2%29%5E3%5Ctimes%20%28xy%29%5E5%3D4%5E3%5Ctimes%20x%5E3%5Ctimes%20%28y%5E2%29%5E3%5Ctimes%20x%5E5%20%5Ctimes%20y%5E5%5C%5C%5C%5C%3D64%5Ctimes%20x%5E%7B3%2B5%7D%5Ctimes%20y%5E%7B5%2B6%7D%5C%5C%5C%5C%3D64x%5E8y%5E%7B11%7D%5C%5C%5C%5C10.%282%5Ctimes%20t%5E3%29%5E3%280.4%5Ctimes%20r%29%5E2%3D2%5E3%20%5Ctimes%20%28t%5E3%29%5E3%5Ctimes%20%280.4%29%5E2%20%5Ctimes%20r%5E2%3D8%5Ctimes%20t%5E9%20%5Ctimes%200.16%20%5Ctimes%20r%5E2%3D1.28r%5E2t%5E9)
8. A number raised to a negative exponent is negative.
Explaining with the help of few examples
![1.2^{-3}=\frac{1}{2^3}=\frac{1}{8}\\\\ 2.(-3)^{-3}=\frac{1}{(-3)^{3}}=\frac{-1}{27}](https://tex.z-dn.net/?f=1.2%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B2%5E3%7D%3D%5Cfrac%7B1%7D%7B8%7D%5C%5C%5C%5C%202.%28-3%29%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B%28-3%29%5E%7B3%7D%7D%3D%5Cfrac%7B-1%7D%7B27%7D)
Option C: Sometimes
1.Option B
2.Option A
3.Option C
4.Option A
5.Option D
6. ![81 \times 10^6](https://tex.z-dn.net/?f=81%20%5Ctimes%2010%5E6)
7.Option B
8.Option C
9.Option A
10.Option ![1.28 r^2 \times t^9](https://tex.z-dn.net/?f=1.28%20r%5E2%20%5Ctimes%20t%5E9)
The answer and explanation in the pic below
Good luck,!
If helped..mark brainliest please ;)
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.
Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).
In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.
Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.
Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.
The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?