Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
10*5+10*5*1 I think this is the right way
x+82+y
______________ =87
3
y-x=17
87,98, and 82.
1) addition property , you add the -3 over
2) division property , you divide by 6x
3)multiplication property , multiply the 3 by 5 to solve for x .
