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Kipish [7]
2 years ago
14

Every 1 have a great day. If sum 1 pull you down get back up Have a good day

Mathematics
1 answer:
dmitriy555 [2]2 years ago
4 0

Answer:

I hope you have a great day too

You might be interested in
The price of one sack of rice is Rs. 1,850.if wages charge Rs. 70 was added, find it price.​
Yuliya22 [10]

Answer:

The total price of the Rice sack is Rs 1920.

Step-by-step explanation:

The price of 1 sack of rice = Rs. 1,850

Wages Charge = Rs. 70

Now, the total price = Price of the Rice + Wages Charge

= Rs. 1,850 + Rs. 70

= Rs. 1920

or,  the total price = Rs. 1920

Hence, the total price of the Rice sack is Rs 1920.

8 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
loris [4]

Answer:

for me the answer was c not sure if you will get it correct but again the answer for me was C

Step-by-step explanation:

5 0
2 years ago
An element with mass 330 grams decays by 25. 5% per minute. How much of the element is remaining after 5 minutes, to the nearest
yaroslaw [1]

The amount of mass after 5 minutes is 75.74 grams.

It is given that

The amount initially = 330grams

After every minute mass decays by 25.5%

<h3>What is the percentage?</h3>

The percentage is the value per hundred.

Amount after 1 min = 330-330*25.5/100 = 245.85grams

Amount after 2 min = 245.85-245.85*25.5/100 = 183.16grams

Amount after 3min = 183.16-183.16*25.5/100 = 136.45grams

Amount after 4 min = 136.45-136.45*25.5/100= 101.66grams

Amount after 5 min =101.66-101.66*25.5/100 = 75.74grams

Therefore, the amount of mass after 5 minutes is 75.74 grams.

To get more about percentage visit:

brainly.com/question/24304697

7 0
2 years ago
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
3 years ago
A 12 ft ladder is place 5 feet from a build. Approximately how high does the ladder reach
kodGreya [7K]
The answer is C, 11ft.
6 0
2 years ago
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