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2 years ago

Find the volume of the rectangular prism pls help me-

Mathematics

2 answers:

alekssr [168]2 years ago

5 0

This ise 105 units cubed

nirvana33 [79]2 years ago

3 0

Answer:

5×3×7=105

Step-by-step explanation:

Volume is length × breadth × height

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Please help !!!! she said 2 of them were the answer

Margaret [11]

Answer:

3 for x not equal to zero

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2 years ago

A rectangle measures 3 feet by 24 inches. Find the area of the rectangle in square feet.

Setler79 [48]

72 plz give brainlliest

4 0

2 years ago

Read 2 more answers

PLEASE HELP!!!

GalinKa [24]

Answer:

14-5i

Step-by-step explanation:

Distribute using FOIL

12+3i-8i-2i^2

i^2 = -1

12+3i-8i-2(-1)

12+3i-8i+2

Combine like terms

14-5i

4 0

2 years ago

How many real-number solutions does the equation have?

Nataly_w [17]

Answer:

Option b. Two solutions

Step-by-step explanation:

In order to find how many real number solutions the equation has we have to solve it

Given equation: -4x² + 10x + 6 = 0

taking 2 common from the equation

2(-2x² + 5x + 3) = 0

-2x² + 5x + 3 = 0

taking minus sign common from the above equation

2x² - 5x - 3 = 0

We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²

2x² - 6x + x - 3 = 0

taking common above

2x(x-3) + 1(x-3) = 0

taking (x-3) common

(2x+1)(x-3) = 0

2x + 1 = 0

2x = -1

x = $\frac{-1}{2}$

x - 3 = 0; x = 3

the solutions are

$x=\frac{-1}{2},3$

Both values are real numbers, therefore correct option is b

7 0

3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

2 years ago