Answer:
(x - 2) and (x + 3) is a factor of: 2x² + 2x - 12
Step-by-step explanation:
2x² + 2x - 12 given equation
Now divide it by 2 we get,
x² + x - 6
then
x² + x - 6
x² + 3x - 2x - 6
x(x + 3) - 2(x + 3)
<em><u>(x - 2) (x + 3)</u></em>
Δ=88
1) Using the Quadratic Equation to Solve
3x²-8x+1=3
3x²-8x+1-3=3-3
3x² -8x -2=0
2)Let's find the discriminant
Δ= (-8)²-4(3)(-2)
Δ=64 -4(3)(-2)
Δ=88
For this case, we must represent the numbers that are included between -4 and 6. Let "x" be the variable that represents these numbers, then we have:
If the set includes -4 and 6 then we have:
Answer:
or
Answer:
g(x) = |x+3| - 5
Step-by-step explanation:
Let y = f(x)
⇒y = |x+3|
When y is replaced by Y + k, the graph of y = f(x) shifts k units down
⇒ y replaced by Y + 5 translates the graph of y = f(x) 5 units down
∴ Y = g(x) is represented by Y + 5 = |x+3|
⇒ Y = |x+3| - 5
or <u>g(x) = |x+3| - 5</u>
