Answer: Based on the graph, what is the initial value of the linear relationship?
A coordinate plane is shown. A line passes through the x axis at negative 3 and the y axis at 5.
−4
−3
five over three
5
Answer:
8a^3.
Step-by-step explanation:
(a+b)^3=a^3+b^3+3a^2b+3ab^2
(a-b)^3=a^3-b^3-3a^2b+3ab^2
(a+b)^3+(a-b)^3=2a^3+6ab^2
According to the question
(a+b)^3+(a-b)^3+6a(a^2-b^2)
Put in the value
=2a^3+6ab^2 +6a^3–6ab^2
=8a^3
Let's find out.
David needs to score an average of 145 across all four games, so first we do:
145 × 4 = 580
Then we add all the scores he currently has:
139 + 143 + 144 = 426
Then we subtract 426 from 580 to find out how much he needs to score for his fourth:
580 - 426 = 154
David needs to score 154 on his 4th game to have an average score of 145 for all 4 games.
Answer: 5
Step-by-step explanation: x means 5
