Can someone help me with 42 divided by 9

The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of the games did they win?

Amanda [17]

They won 6/11 games.

When you add the games they won, lost, and tied you see that they played a total of 11 games. It tells you that they won 6 games so you would put 6 as the numerator and 11 as the denominator and get 6/11.

3 0

3 years ago

Read 2 more answers

The area of the square is 100 square centimeters. What is the area of the circle?

swat32

Answer:

Since the question is incomplete, see the figure attached and the explanation below.

Explanation:

Since the figure is missing, I enclose the figure of a square inscribed in a circle.

Since the <em>area of a square</em> is the side length squared, you can determine the side length:

Area = (side length)²

100 cm² = (side lenght)²

$side\text{ }length=\sqrt{100cm^2}=10cm$

From the side length, you can find the diagonal of the square, which is equal to the diameter of the circle, using the Pythagorean theorem:

diagonal² = (10cm)² + (10cm)² = 2 × (10cm)²

$diagonal=\sqrt{2\times (10cm)^2}\\ \\ diagonal=10\sqrt{2} cm$

The area of the circle is π (radius)².

radius = diameter/2 = diagonal/2

$area= \pi \times (5\sqrt{2}cm)^2=50\pi cm^2$

6 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago

Find the slope between (2, 5) and (7,3).

beks73 [17]

Answer:

-2/5

Step-by-step explanation:

y2-y1

-------- is -2/5 . after . u plug the 2 pairs

x2-x1

7 0

2 years ago

a tennis supply store pays a wholesaler $90 for a tennis racquet and sells it for $144 what is the markup rate

dexar [7]

Markup is the difference between the cost of a good or service and its selling price. A markup is added onto the total cost incurred by the producer of a good or service in order to create a profit. The total cost reflects the total amount of both fixed and variable expenses to produce and distribute a product.so it would be 144 - 90 = 54. $54 would be the markup.

6 0

3 years ago