the blue lake trail is 11 3/8 miles long. gemma has hiked 2 1/2 miles each hour for 3 hours. how far is she from the end?

2x - y = 0 4x - y = 0

Delicious77 [7]

Answer:

what's the question here ?

6 0

2 years ago

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Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the

igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0

2 years ago

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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3>Given :-</h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

We have to find the distance between the golf ball and the center of the green .

<h3>Let's Begin :-</h3>

Let assume that the distance between the golf ball and central of green is x

Here, 

Distance between marker and centre of green is 150 yards
That is, Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
That is, Angle = 100°
The golfer peces off 30 yards to his ball
That is, Base = 30 yards

According to the law of cosine :-

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

So, For Hypotenuse law of cosine will be :-

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

Subsitute the required values,

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Which expression is equivalent to -4(w-1) 4w-4 4w -4w+4 -5w None of the above

dimulka [17.4K]

Answer:

-4w+4

Step-by-step explanation:

5 0

2 years ago

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Any mha fans.............................

lidiya [134]

Answer:

you bet

Step-by-step explanation:

6 0

2 years ago

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