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Anika [276]
3 years ago
9

9. (3x + 4y)² – (3z) 2square​

Mathematics
2 answers:
rodikova [14]3 years ago
5 0
Solution: (3x + 4y - 3z) x (3x + 4y + 3z)
S_A_V [24]3 years ago
4 0

Answer:

(3x + 4y - 3z)(3x + 4y + 3z)

Step-by-step explanation:

(3x + 4y)² - (3z)² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Here a = 3x + 4y and b = 3z, then

(3x + 4y)² - (3z)²

= (3x + 4y - 3z)(3x + 4y + 3z) ← in factored form

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Pls help its due at 11:10
arlik [135]

Answer:

firstly

we all know that the angles of a triangle they all add up to 180° meaning when you add them all they must give you 180°

88°+33°+L = 180° ( sum of angle in a ∆)

121° + L = 180°

L = 180° - 121°

L = 59°

Step-by-step explanation:

first you you must add all your angles and all equal to 180°

that you add the like terms

than you transpose 121° to the right hand side

5 0
3 years ago
You are traveling in a car. Your speed is 40 miles per hour. What is your speed in feet per minute?
Korvikt [17]

Answer:

3520.176 feet per minute

Step-by-step explanation:

First, we must convert 40 miles per hour (mph) to miles per minute (mpm):

40 mph = 40 miles/hour / 60 minutes/hour = 0.6667 miles per minute

Next, we convert miles per minute to feet per minute by multiplying 5280 ft per mile:

0.6667 mpm = 0.6667 miles/minute * 5280 ft/mile = 3520.176 feet per minute

8 0
2 years ago
Determine if the statement below is always, sometimes, or never true. There are 250 degrees in the sum of the interior angles of
ZanzabumX [31]
It would never be true.
5 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
3 years ago
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