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Anika [276]
3 years ago
9

9. (3x + 4y)² – (3z) 2square​

Mathematics
2 answers:
rodikova [14]3 years ago
5 0
Solution: (3x + 4y - 3z) x (3x + 4y + 3z)
S_A_V [24]3 years ago
4 0

Answer:

(3x + 4y - 3z)(3x + 4y + 3z)

Step-by-step explanation:

(3x + 4y)² - (3z)² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Here a = 3x + 4y and b = 3z, then

(3x + 4y)² - (3z)²

= (3x + 4y - 3z)(3x + 4y + 3z) ← in factored form

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3 years ago
EQAO Watch Sammy and Pippa's teacher gives them a homework question to solve. She tells them to plot the points A(5, -1), B(9, 4
Alona [7]

Answer:

None of them are correct. The shape in their homework is a rectangle

Step-by-step explanation:

I would be determining my answer using Length

To find the length of the sides, when you have vertices (x₁, x₂)and (y₁, y₂) we use the formula

√(x₂-x₁)²-(y₂-y₁)²

A(5, -1), B(9, 4), C(15, 1) and D(11, -4)

Side/ Length AB = A(5, -1), B(9, 4)

√(x₂-x₁)²-(y₂-y₁)²

= √(9 - 5)² + (4 - (-1))²

= √4² + 5²

= √16 + 25

= √41

Side/ Length BC = , B(9, 4), C(15, 1)

= √(x₂-x₁)²-(y₂-y₁)²

= √(15 - 9)² + ( 1 - 4)²

= √6² + -3²

= √36 + 9

= √45

Side/ Length CD = C(15, 1) and D(11, -4)

√(x₂-x₁)²-(y₂-y₁)²

= √(11 - 15)² + (-4 - 1)²

= √-4² + -5²

= √16 + 25

= √41

Side/ Length AD = A(5, -1), D(11, -4)

√(x₂-x₁)²-(y₂-y₁)²

= √(11- 5)² + (-4 - (-1))²

= √6² + 3²

= √36 + 9

= √45

From the Calculations above ,

AB = √41

BC = √45

CD = √41

AD = √45

A square and a rhombus are shapes with 4 sides and all their sides are equal to each other.

From the above calculation, we can see that

We can see that Length AB = Length CD

Length BC = Length AD

This means , the Opposite sides only are equal to each other.

Therefore, none of them is correct. The shape in their homework is a rectangle

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