Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
In case of Alpha:
Number of oranges = 18
Number of apples = 9
In case of Beta :
Number of oranges = 16
Number of apples = 4
We need to find the opportunity cost of producing 1 orange for Alpha and Beta.
Opportunity cost for Alpha is given by
![\dfrac{\text{number of sacrificing units}}{\text{Number of gaining units}}\\\\=\dfrac{18}{9}=2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7Bnumber%20of%20sacrificing%20units%7D%7D%7B%5Ctext%7BNumber%20of%20gaining%20units%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B18%7D%7B9%7D%3D2)
Opportunity cost for Beta is given by
![\dfrac{16}{4}=4](https://tex.z-dn.net/?f=%5Cdfrac%7B16%7D%7B4%7D%3D4)
Hence, Opportunity cost for producing 1 orange for Alpha and Beta are 9 apples and 4 apples respectively.
Hence, Option 'B' is correct.
16.8-8.3=8.5
You round the numbers with decimals to their tenths place and then subtract normally.
8, 11, 12, 13, 16, 42
Add together and divide by 6 to get the mean.
102/6 = 17
Find the middle of the data for the median.
(12 + 13)/2 = 12.5
The mean is 17, the median is 12.5, and the mean is more affected by the outlier. 17 (the mean) is not a good measure of center.