Answer:
addition
Step-by-step explanation:
18 (<u> d </u> - 9 ) = 198
3
divide both side by 18
<u> d </u> - 9 = <u> 198 </u>
3 18
<u> d </u> - 9 = 11
3
multiply both sides by 3
d - 27 = 33
add 27 to both sides
d = 33 + 27
lastly, add them together
d = 60
therefore, the last step is addition
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

Answer:
The explicit form is 
Step-by-step explanation:
The explicit form of a geometric sequence is given by:

where an is the nth term, a is the first term of the sequence and r is the common ratio.
In this case:
a=162
The value of the common ratio is obtained by dividing one term by the previous term.
For the first and second terms:
108/162=2/3
For the second and third terms (In order to prove that 2/3 is the common ratio)
72/108=2/3
Therefore:
r=2/3
Replacing a and r in the formula:

B is the best strategy. (You mentioned an option D, but it's not shown in your question!!)
Answer:
57.2
Step-by-step explanation:
Have a great day